Chess Game
Arjun Bharat vs Sander Van Eijk
16. HZ Open, 2012 · Result 1–0 · English Opening: Symmetrical Variation, Three Knights, Fianchetto Variation (A37).
Sander Van Eijk0
Arjun Bharat1
Notation · 59 moves
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1. Nf3 c5 2. c4 Nc6 3. g3 g6 4. Bg2 Bg7 5. O-O e5 6. Nc3 Nge7 7. a3 O-O 8. Rb1 a5 9. Ne1 d6 10. Nc2 Be6 11. Ne3 f5 12. d3 f4 13. Ned5 Bh6 14. e3 fxe3 15. Bxe3 Bxe3 16. fxe3 Rb8 17. Qd2 Rf7 18. Rxf7 Bxf7 19. Rf1 Be6 20. Rf6 Nxd5 21. Nxd5 Bf5 22. e4 Bc8 23. Qh6 Ne7 24. Qg5 Nc6 25. h4 Bd7 26. h5 Be8 27. Qh6 Bf7 28. Rxf7 Kxf7 29. Qxh7+ Ke6 30. Bh3# 1–0
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About this game
This chess game between Arjun Bharat (2286) and Sander Van Eijk (2422) was played at 16. HZ Open in 2012 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Three Knights, Fianchetto Variation (A37). Step through every move on the interactive board above, or open it on the CipherChess board to analyse the game with the engine. You can also explore more games by Arjun Bharat and Sander Van Eijk from the CipherChess mega database.