Angelo Costa Barros vs Felipe Guimaraes De Souza
2. Rio Chess Open 2023, 2023 · Result 0–1 · Bogo-Indian Defense (E11).
Turn this game into your next win
Replay Angelo Costa Barros vs Felipe Guimaraes De Souza with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Angelo Costa Barros (1737)
- Black
- Felipe Guimaraes De Souza (2025)
- Result
- 0–1
- Event
- 2. Rio Chess Open 2023
- Year
- 2023
- Opening
- Bogo-Indian Defense (E11)
About this chess game
This chess game between Angelo Costa Barros (1737) and Felipe Guimaraes De Souza (2025) was played at 2. Rio Chess Open 2023 in 2023 and finished 0–1. The opening was the Bogo-Indian Defense (E11). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Angelo Costa Barros games or Felipe Guimaraes De Souza games? This Angelo Costa Barros vs Felipe Guimaraes De Souza encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Bogo-Indian Defense.
Frequently asked questions
Who won Angelo Costa Barros vs Felipe Guimaraes De Souza?
Angelo Costa Barros vs Felipe Guimaraes De Souza (2023) finished 0–1, a win for Felipe Guimaraes De Souza.
What opening was played in Angelo Costa Barros vs Felipe Guimaraes De Souza?
The game opened with the Bogo-Indian Defense (ECO E11).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Angelo Costa Barros vs Felipe Guimaraes De Souza, or open it on the CipherChess analysis board to review it with the Stockfish engine.