Michel Barbaric vs Alexander Hoerl
Bayern-chI Bank Hofmann 2nd, 1998 · Result ½–½ · Indian Defense: Budapest Defense (A52).
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Game details
- White
- Michel Barbaric
- Black
- Alexander Hoerl (1858)
- Result
- ½–½
- Event
- Bayern-chI Bank Hofmann 2nd
- Year
- 1998
- Opening
- Indian Defense: Budapest Defense (A52)
About this chess game
This chess game between Michel Barbaric and Alexander Hoerl (1858) was played at Bayern-chI Bank Hofmann 2nd in 1998 and finished ½–½. The opening was the Indian Defense: Budapest Defense (A52). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Michel Barbaric games or Alexander Hoerl games? This Michel Barbaric vs Alexander Hoerl encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Budapest Defense.
Frequently asked questions
Who won Michel Barbaric vs Alexander Hoerl?
Michel Barbaric vs Alexander Hoerl (1998) finished ½–½, and the game was drawn.
What opening was played in Michel Barbaric vs Alexander Hoerl?
The game opened with the Indian Defense: Budapest Defense (ECO A52).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Michel Barbaric vs Alexander Hoerl, or open it on the CipherChess analysis board to review it with the Stockfish engine.