Abraham Baratz vs Henri Bertrand
1927 · Result 1–0 · Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (E42).
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Game details
- White
- Abraham Baratz
- Black
- Henri Bertrand
- Result
- 1–0
- Year
- 1927
- Opening
- Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (E42)
About this chess game
This chess game between Abraham Baratz and Henri Bertrand was played in 1927 and finished 1–0. The opening was the Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (E42). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Abraham Baratz games or Henri Bertrand games? This Abraham Baratz vs Henri Bertrand encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation.
Frequently asked questions
Who won Abraham Baratz vs Henri Bertrand?
Abraham Baratz vs Henri Bertrand (1927) finished 1–0, a win for Abraham Baratz.
What opening was played in Abraham Baratz vs Henri Bertrand?
The game opened with the Nimzo-Indian Defense: Rubinstein System, Rubinstein Variation (ECO E42).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Abraham Baratz vs Henri Bertrand, or open it on the CipherChess analysis board to review it with the Stockfish engine.