Rohan Bansal vs Steven J Burke
4NCL, 2012 · Result ½–½ · Queen's Pawn Game (A40).
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Game details
- White
- Rohan Bansal (1791)
- Black
- Steven J Burke (2046)
- Result
- ½–½
- Event
- 4NCL
- Year
- 2012
- Opening
- Queen's Pawn Game (A40)
About this chess game
This chess game between Rohan Bansal (1791) and Steven J Burke (2046) was played at 4NCL in 2012 and finished ½–½. The opening was the Queen's Pawn Game (A40). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Rohan Bansal games or Steven J Burke games? This Rohan Bansal vs Steven J Burke encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game.
Frequently asked questions
Who won Rohan Bansal vs Steven J Burke?
Rohan Bansal vs Steven J Burke (2012) finished ½–½, and the game was drawn.
What opening was played in Rohan Bansal vs Steven J Burke?
The game opened with the Queen's Pawn Game (ECO A40).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Rohan Bansal vs Steven J Burke, or open it on the CipherChess analysis board to review it with the Stockfish engine.