Jose Avellanas Tomas vs Maria Eizaguerri Floris
2015 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Jose Avellanas Tomas vs Maria Eizaguerri Floris with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Jose Avellanas Tomas (1930)
- Black
- Maria Eizaguerri Floris (1972)
- Result
- 0–1
- Year
- 2015
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Jose Avellanas Tomas (1930) and Maria Eizaguerri Floris (1972) was played in 2015 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Jose Avellanas Tomas games or Maria Eizaguerri Floris games? This Jose Avellanas Tomas vs Maria Eizaguerri Floris encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Jose Avellanas Tomas vs Maria Eizaguerri Floris?
Jose Avellanas Tomas vs Maria Eizaguerri Floris (2015) finished 0–1, a win for Maria Eizaguerri Floris.
What opening was played in Jose Avellanas Tomas vs Maria Eizaguerri Floris?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Jose Avellanas Tomas vs Maria Eizaguerri Floris, or open it on the CipherChess analysis board to review it with the Stockfish engine.