Stephan Arounopoulos vs Roland Muth
2007 · Result 0–1 · Indian Defense: Normal Variation (A50).
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Game details
- White
- Stephan Arounopoulos (2003)
- Black
- Roland Muth (2127)
- Result
- 0–1
- Year
- 2007
- Opening
- Indian Defense: Normal Variation (A50)
About this chess game
This chess game between Stephan Arounopoulos (2003) and Roland Muth (2127) was played in 2007 and finished 0–1. The opening was the Indian Defense: Normal Variation (A50). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Stephan Arounopoulos games or Roland Muth games? This Stephan Arounopoulos vs Roland Muth encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Normal Variation.
Frequently asked questions
Who won Stephan Arounopoulos vs Roland Muth?
Stephan Arounopoulos vs Roland Muth (2007) finished 0–1, a win for Roland Muth.
What opening was played in Stephan Arounopoulos vs Roland Muth?
The game opened with the Indian Defense: Normal Variation (ECO A50).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Stephan Arounopoulos vs Roland Muth, or open it on the CipherChess analysis board to review it with the Stockfish engine.