David Arnett vs M. Royzen
Marshall junior, 1992 · Result 0–1 · Indian Defense: Normal Variation (A50).
Turn this game into your next win
Replay David Arnett vs M. Royzen with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- David Arnett (2335)
- Black
- M. Royzen
- Result
- 0–1
- Event
- Marshall junior
- Year
- 1992
- Opening
- Indian Defense: Normal Variation (A50)
About this chess game
This chess game between David Arnett (2335) and M. Royzen was played at Marshall junior in 1992 and finished 0–1. The opening was the Indian Defense: Normal Variation (A50). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more David Arnett games or M. Royzen games? This David Arnett vs M. Royzen encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Normal Variation.
Frequently asked questions
Who won David Arnett vs M. Royzen?
David Arnett vs M. Royzen (1992) finished 0–1, a win for M. Royzen.
What opening was played in David Arnett vs M. Royzen?
The game opened with the Indian Defense: Normal Variation (ECO A50).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of David Arnett vs M. Royzen, or open it on the CipherChess analysis board to review it with the Stockfish engine.