Teodor Anton vs Bogdan-Alexandru Heutschi
ROM Ch U14, date unknown · Result 1–0 · Italian Game (C50).
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Game details
- White
- Teodor Anton (2038)
- Black
- Bogdan-Alexandru Heutschi (1730)
- Result
- 1–0
- Event
- ROM Ch U14
- Opening
- Italian Game (C50)
About this chess game
This chess game between Teodor Anton (2038) and Bogdan-Alexandru Heutschi (1730) was played at ROM Ch U14 and finished 1–0. The opening was the Italian Game (C50). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Teodor Anton games or Bogdan-Alexandru Heutschi games? This Teodor Anton vs Bogdan-Alexandru Heutschi encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Italian Game.
Frequently asked questions
Who won Teodor Anton vs Bogdan-Alexandru Heutschi?
Teodor Anton vs Bogdan-Alexandru Heutschi finished 1–0, a win for Teodor Anton.
What opening was played in Teodor Anton vs Bogdan-Alexandru Heutschi?
The game opened with the Italian Game (ECO C50).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Teodor Anton vs Bogdan-Alexandru Heutschi, or open it on the CipherChess analysis board to review it with the Stockfish engine.