Brendan Anderson vs Yin Lin Wee
Hong Kong International Open Chess Championship 2025 | Open, 2025 · Result 1–0 · English Opening: Symmetrical Variation, Four Knights Variation (A35).
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Game details
- White
- Brendan Anderson (2010)
- Black
- Yin Lin Wee (1855)
- Result
- 1–0
- Event
- Hong Kong International Open Chess Championship 2025 | Open
- Year
- 2025
- Opening
- English Opening: Symmetrical Variation, Four Knights Variation (A35)
About this chess game
This chess game between Brendan Anderson (2010) and Yin Lin Wee (1855) was played at Hong Kong International Open Chess Championship 2025 | Open in 2025 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Four Knights Variation (A35). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Brendan Anderson games or Yin Lin Wee games? This Brendan Anderson vs Yin Lin Wee encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Four Knights Variation.
Frequently asked questions
Who won Brendan Anderson vs Yin Lin Wee?
Brendan Anderson vs Yin Lin Wee (2025) finished 1–0, a win for Brendan Anderson.
What opening was played in Brendan Anderson vs Yin Lin Wee?
The game opened with the English Opening: Symmetrical Variation, Four Knights Variation (ECO A35).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Brendan Anderson vs Yin Lin Wee, or open it on the CipherChess analysis board to review it with the Stockfish engine.