Henry Henville Amadio vs John Arthur Kinman
Sydney, 1928 · Result 0–1 · Semi-Slav Defense: Meran Variation, Lundin Variation (D47).
Turn this game into your next win
Replay Henry Henville Amadio vs John Arthur Kinman with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- Black
- John Arthur Kinman
- Result
- 0–1
- Event
- Sydney
- Year
- 1928
- Opening
- Semi-Slav Defense: Meran Variation, Lundin Variation (D47)
About this chess game
This chess game between Henry Henville Amadio and John Arthur Kinman was played at Sydney in 1928 and finished 0–1. The opening was the Semi-Slav Defense: Meran Variation, Lundin Variation (D47). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Henry Henville Amadio games or John Arthur Kinman games? This Henry Henville Amadio vs John Arthur Kinman encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Semi-Slav Defense: Meran Variation, Lundin Variation.
Frequently asked questions
Who won Henry Henville Amadio vs John Arthur Kinman?
Henry Henville Amadio vs John Arthur Kinman (1928) finished 0–1, a win for John Arthur Kinman.
What opening was played in Henry Henville Amadio vs John Arthur Kinman?
The game opened with the Semi-Slav Defense: Meran Variation, Lundin Variation (ECO D47).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Henry Henville Amadio vs John Arthur Kinman, or open it on the CipherChess analysis board to review it with the Stockfish engine.