Horst Alber vs Wiede Friedrich
2018 · Result 1–0 · Semi-Slav Defense: Meran Variation, Lundin Variation (D47).
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Game details
- White
- Horst Alber (2290)
- Black
- Wiede Friedrich (2326)
- Result
- 1–0
- Year
- 2018
- Opening
- Semi-Slav Defense: Meran Variation, Lundin Variation (D47)
About this chess game
This chess game between Horst Alber (2290) and Wiede Friedrich (2326) was played in 2018 and finished 1–0. The opening was the Semi-Slav Defense: Meran Variation, Lundin Variation (D47). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Horst Alber games or Wiede Friedrich games? This Horst Alber vs Wiede Friedrich encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Semi-Slav Defense: Meran Variation, Lundin Variation.
Frequently asked questions
Who won Horst Alber vs Wiede Friedrich?
Horst Alber vs Wiede Friedrich (2018) finished 1–0, a win for Horst Alber.
What opening was played in Horst Alber vs Wiede Friedrich?
The game opened with the Semi-Slav Defense: Meran Variation, Lundin Variation (ECO D47).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Horst Alber vs Wiede Friedrich, or open it on the CipherChess analysis board to review it with the Stockfish engine.