Oscar Marino Agudelo Pineres vs Bernardo Barrios
2019 · Result ½–½ · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Oscar Marino Agudelo Pineres vs Bernardo Barrios with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Oscar Marino Agudelo Pineres (1989)
- Black
- Bernardo Barrios (1888)
- Result
- ½–½
- Year
- 2019
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Oscar Marino Agudelo Pineres (1989) and Bernardo Barrios (1888) was played in 2019 and finished ½–½. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Oscar Marino Agudelo Pineres games or Bernardo Barrios games? This Oscar Marino Agudelo Pineres vs Bernardo Barrios encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Oscar Marino Agudelo Pineres vs Bernardo Barrios?
Oscar Marino Agudelo Pineres vs Bernardo Barrios (2019) finished ½–½, and the game was drawn.
What opening was played in Oscar Marino Agudelo Pineres vs Bernardo Barrios?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Oscar Marino Agudelo Pineres vs Bernardo Barrios, or open it on the CipherChess analysis board to review it with the Stockfish engine.