Ranganath Aadya vs Vladimir A Romanov
Hong Kong Open 2025, 2025 · Result 0–1 · Italian Game: Classical Variation (C54).
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Game details
- White
- Ranganath Aadya (1809)
- Black
- Vladimir A Romanov (1538)
- Result
- 0–1
- Event
- Hong Kong Open 2025
- Year
- 2025
- Opening
- Italian Game: Classical Variation (C54)
About this chess game
This chess game between Ranganath Aadya (1809) and Vladimir A Romanov (1538) was played at Hong Kong Open 2025 in 2025 and finished 0–1. The opening was the Italian Game: Classical Variation (C54). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Ranganath Aadya games or Vladimir A Romanov games? This Ranganath Aadya vs Vladimir A Romanov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Italian Game: Classical Variation.
Frequently asked questions
Who won Ranganath Aadya vs Vladimir A Romanov?
Ranganath Aadya vs Vladimir A Romanov (2025) finished 0–1, a win for Vladimir A Romanov.
What opening was played in Ranganath Aadya vs Vladimir A Romanov?
The game opened with the Italian Game: Classical Variation (ECO C54).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Ranganath Aadya vs Vladimir A Romanov, or open it on the CipherChess analysis board to review it with the Stockfish engine.